linux 简单服务启动、关闭脚本

linux 简单服务启动、关闭脚本

假如我们的目录结构如下：

/home/project/bin/shell # 脚本所在目录
/home/project/TestServer/bin # 可执行程序目录
/home/project/TestServer/lib # 依赖库目录

服务名为：TestServer

启动脚本start.sh：

#!/bin/bash
appName=TestServer
process=`ps -ef | grep ${appName} | grep -v grep | awk '{print $2}'`;
if [ "$process" == "" ]; then
    thisDir="$(cd `dirname "$0"` && pwd )"
    runDir="${thisDir}/../${appName}/bin"
    libDir="${thisDir}/../${appName}/lib"
    cd $runDir
    export LD_LIBRARY_PATH=$libDir
    nohup "$runDir"/$appName &
    process=`ps -ef | grep ${appName} | grep -v grep | awk '{print $2}'`;
    sleep 1s
    echo "------------${appName} start success, pid is ${process}------------"
else
    echo "------------${appName} is always running, pid is ${process}------------"
fi

关闭脚本stop.sh

#!/bin/bash
ps -ef | grep TestServer | grep -v grep | awk '{print $2}' | xargs kill -9
echo "------------TestServer is stopped successfully.-------------"

简单解释下：
如果进程已经在运行就直接返回。

process=`ps -ef | grep ${appName} | grep -v grep | awk '{print $2}'`;

获取appName的进程ID，这个语句会过滤掉grep本身，进程ID在第2列。

thisDir="$(cd `dirname "$0"` && pwd )"

获取当前脚本所在目录，赋值给变量thisDir

export LD_LIBRARY_PATH=$libDir

导入程序运行依赖库

nohup "$runDir"/$appName &

不挂断在后台运行